两个有序链表合并

· 约 1 分钟阅读 · 次阅读 leetcode

迭代方法直接处理

# Definition for singly-linked list.
# class ListNode:
#     def __init__(self, val=0, next=None):
#         self.val = val
#         self.next = next
class Solution:
    def mergeTwoLists(self, list1: Optional[ListNode], list2: Optional[ListNode]) -> Optional[ListNode]:
        dummy = ListNode()
        cur = dummy
        while list1 and list2:
            if list1.val < list2.val:
                r = list1
                list1 = list1.next
            else:
                r = list2
                list2 = list2.next
            # print(r.val, cur.val)
            cur.next = r
            cur = r
        while list1:
            cur.next = list1
            break
        while list2:
            cur.next = list2
            break
        return dummy.next

递归方法

# Definition for singly-linked list.
# class ListNode:
#     def __init__(self, val=0, next=None):
#         self.val = val
#         self.next = next
class Solution:
    def mergeTwoLists(self, list1: Optional[ListNode], list2: Optional[ListNode]) -> Optional[ListNode]:
        if not list1:
            return list2
        if not list2:
            return list1
        if list1.val < list2.val:
            list1.next = self.mergeTwoLists(list1.next, list2)
            return list1
        else:
            list2.next = self.mergeTwoLists(list1, list2.next)
            return list2